MATH 321 – Mathematical Statistics I
October 28, 2025
For any random variable \(X\), the moment-generating function (MGF) \(M_X(t)\) of a random variable \(X\) is: \[ M_X(t) = E[e^{tX}]. \]
Example:
Theorem: The moment-generating function has the properties that:
Example: Given that the MGF of \(X \sim \text{Exponential}(\lambda)\) is \(M_X(t) = (1 − \beta t)^{-1}\), prove that \(E[X] = \beta\) and \(V(X) = \beta^2\) using it.
Theorem: Let \(X\) and \(Y\) be independent random variables. Let \(Z = X + Y\). Then \[ M_Z(t) = M_X(t) M_Y(t). \]
Corollary: Consider independent random variables \(X_1, \dots, X_N\). Let \(Z = \sum_{i=1}^N X_i\) be the sum of random variables. Then the MGF of \(Z\) is \[ M_Z(t) = \prod_{i=1}^N M_{X_i}(t). \]
The moment-generating function of a random variable uniquely defines the distribution.
Theorem: Let \(M_X(t)\) and \(M_Y(t)\) denote the moment-generating functions of random variables \(X\) and \(Y\). If both moment-generating functions and \(M_X(t) = M_Y(t)\) for all \(t \in \mathbb{R}\), then \(X\) and \(Y\) have the same probability distribution.
The moment-generating function does not exist for all distributions. For example, the Cauchy distribution does not have an MGF.
Theorem: Let \(M_X(t)\) and \(M_Y(t)\) denote the moment-generating functions of random variables \(X\) and \(Y\). If both moment-generating functions and \(M_X(t) = M_Y(t)\) for all \(t \in \mathbb{R}\), then \(X\) and \(Y\) have the same probability distribution.
If these independent random variables are further assumed to be identically distributed, the moment-generating function is \[ M_Z(t) = \Big(M_{X_1}(t)\Big)^N. \]
Examples:
There is a related function that does exist for all distributions, the characteristic function \(\varphi_X(t)\).
For any random variable \(X\), the characteristic function \(\varphi_X(t)\) of a random variable \(X\) is: \[ \varphi_X(t) = E[e^{itX}]. \]
Properties: