MATH 321 – Mathematical Statistics I
September 22, 2025
Definition: A probability space is a triple \((\Omega, \mathcal{F} , P)\), where \(\Omega\) is the sample space, \(\mathcal{F}\) is the event space, and \(P\) is a probability law (or measure).
Definition: A probability law is a function \(P : \mathcal{F} \to [0,\, 1]\) that maps an event \(A\) to a real number in \([0,\, 1]\). The function must satisfy the axioms of probability:
Non-Negativity: \(P(A) \ge 0\), for any \(A \subseteq \Omega\).
Normalization: \(P(\Omega) = 1\).
Additivity: For any disjoint sets \(\{A_1,\, A_2,\, A_3,\, \dots \}\), it must be true that \[ P \left( \bigcup_{i=1}^\infty A_i \right) = \sum_{i=1}^\infty P(A_i). \]
Corollary: Let \(A \in \mathcal{F}\) be an event. Then:
\(P(\overline{A}) = 1 - P[A]\).
\(P(A) \le 1\).
\(P(\varnothing) = 0\).
Corollary (Unions of Two Non-Disjoint Sets): For any \(A\) and \(B\) in \(\mathcal{F}\), \[ P(A \cup B) = P(A) + P(B) - P(A \cap B). \]
Corollary (Inequalities): Let \(A\) and \(B\) be two events in \(\mathcal{F}\). Then:
\(P(A \cup B) \le P(A) + P(B)\). (Union Bound)
If \(A \subseteq B\), then \(P(A) \le P(B)\).
Theorem (Bayes’ Theorem): For any two events \(A\) and \(B\) such that \(P(A) > 0\) and \(P(B) > 0\), \[ P(A \,\vert\, B) = \frac{P(B \,\vert\, A) P(A)}{P(B)}. \]
Theorem (Law of Total Probability): Let \(\{A_1,\, A_2,\, A_3,\, \dots\}\) be a partition of \(\Omega\), i.e., \(A_1,\, A_2,\, A_3,\, \dots\) are disjoint and \(\Omega = A_1 \cup A_2 \cup \dots\). Then, for any \(B \subseteq \Omega\), \[ P(B) = \sum_{i \in I} P(B \,\vert\, A_i) P(A_i). \]
Corollary: Let \(\{A_1,\, A_2,\, A_3,\, \dots\}\) be a partition of \(\Omega\), i.e., \(A_1,\, A_2,\, A_3,\, \dots\) are disjoint and \(\Omega = A_1 \cup A_2 \cup \dots\). Then, for any \(B \subseteq \Omega\), \[ P(A_j \,\vert\, B) = \frac{P(B \,\vert\, A_j) P(A_j)}{\sum_{i \in I} P(B \,\vert\, A_i) P(A_i)}. \]
Example: Let \(S\) be a (non-empty) set. Then \((S, \mathcal{P}(S), P)\) is a probability space, where \(P(A) = \dfrac{\lvert A \rvert}{\lvert S \rvert}\) for any \(A \in \mathcal{P}(S)\).
Example: Let \(A \subset \Omega\), where \((\Omega,\, \mathcal{F} , P)\) is a probability space and \(P(A) > 0\). Show \(\widehat{P}(B) = \dfrac{P(B \cap A)}{P(A)}\) defines a probability measure on \(\mathcal{F} \cap A\).
Let \((\Omega, \mathcal{F}, P)\) be a probability space.
Definition: A random variable \(X\) is a function \(X : \Omega \to \mathbb{R}\) that maps an outcome \(\xi \in \Omega\) to a number \(X(\xi)\) on the real line.
Definition: A random variable \(Y\) is said to be discrete if it can assume only a finite or countably infinite number of distinct values.
Example: Let \(\Omega\) consist of the outcomes of tossing a (fair) coin three times and let \(X : \Omega \to \mathbb{R}\) be the number of heads that appears.
Definition: The probability mass function (PMF) of a random variable \(X\) is a function which specifies the probability of obtaining a number \(X(\xi) = x\). We denote a probability mass function as: \[ p_X(x) = P(X = x). \] The set of all possible states of \(X\) is denoted as \(X(\Omega)\).
Example: Let \(\Omega\) consist of the outcomes of tossing a (fair) coin three times and let \(X : \Omega \to \mathbb{R}\) be the number of heads that appears. What is the probability mass function (PMF) of this random variable?
Random variables have a graphical representation called a probability histogram.
Theorem: If \(A \subset X(\Omega)\), then the function \(P(A) = \displaystyle\sum_{x \in A} p_X(x)\) is a probability law of \(X(\Omega)\).
Can you prove this?
Definition: Let \(X\) be a discrete random variable with the probability mass function \(p_X(x)\). Then the expected value (or mean) of \(X\), \(E(X)\), is defined to be: \[ E(X) = \sum_x x \, p_X(x). \] If \(p_X(x)\) is an accurate characterization of the population frequency distribution,then \(E(X) = \mu\), the population mean.
Definition: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and \(g(X)\) be a real-valued function of \(X\). Then the expected value of \(g(X)\) is given by: \[ E(g(X)) = \sum_x g(x) \, p_X(x). \]
A specific case of an expected value of a function of a random variables are the moments of the random variables.
The \(n^{th}\) moment of a random variable X is defined as: \[ E(X^n) = \sum_x x^n \, p_X(x). \]
The \(n^{th}\) central moment of a random variable X is defined as: \[ E(X^n) = \sum_x (x-\mu)^n \, p_X(x), \] where \(\mu = E(X)\).
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and \(c\) be a constant. Then \(E(c) = c\).
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\), \(g(X)\) be a function of \(X\), and \(c\) be a constant. Then: \[ E[c \times g(X)] = c \times E[g(X)]. \]
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and \(g_1(X),\, g_2(X),\, \dots,\, g_k(X)\) be \(k\) functions of \(X\). Then: \[ E\left[\sum_{i=1}^k g_i(X)\right] = \sum_{i=1}^k E\big[g_i(X)\big]. \]
\(E(X)\) gives the mean of the population with distribution given by \(p_X(x)\). Now let’s define the variance and standard deviation of this population.
Definition: The variance of a set of measurements is the average of the square of the differences between the values in a set of measurements and their mean, denoted as \(\sigma^2\).
Definition: The standard deviation of \(X\) is the positive square root of \(V(X)\), denoted as \(\sigma\).
Definition: If \(X\) is a random variable with mean \(\mu = E(X)\), the variance of a random variable \(X\) is defined to be the expected value of \((X − \mu)^2\). That is, \[ V(X) = E[(X − \mu)^2]. \]
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and finite mean \(E(X) = \mu\); then: \[ V(X) = E[(X − \mu)^2] = E(X^2) - \big[E(X)\big]^2 \]
This second formula is a lot easier to use!
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and \(c\) be a constant. Then \(V(c) = 0\).
Theorem: Let \(X\) be a discrete random variable with probability mass function \(p_X(x)\) and \(c\) be a constant. Then: \[ V[c \times X] = c^2 \times V[X]. \]
Theorem: Let \(X_1,\, X_2,\, X_3,\, \dots\) be discrete random variables with probability mass functions \(p_{X_1}(x),\, p_{X_2}(x),\, p_{X_3}(x),\, \dots\). Then: \[ V\left[\sum_{i=1}^k X_i \right] = \sum_{i=1}^k V\big[ X_ i \big]. \]