MATH 145 – Calculus I
September 8, 2025
Recall in Lecture #1, we discussed the average rate of change: \[ AV_{[a, b]} = \frac{f(b) - f(a)} {b - a} \]
This tells us the average rate of change across some interval \([a,b]\), but what if we want to know what the rate of change is at some point \((x,f(x))\).
Imagine you’re on a roller coaster. How can you describe and predict how fast you’ll be going at any particular point on the track?
Today we will be discussing the foundation of all calculus going forward: the limit.
\[ \lim_{x \to a} f(x) \]
Everything we will do in future lectures: derivatives, integrals, all the things you may have heard of in terms of calculus are built off the humble limit.
Consider the function \(f(x) = x^2\) at the point \(x=3\). As \(f(x)\) is continuous, as we put \(x\)’s closer and closer to \(3\), we will get values of \(f(x)\) closer and closer and closer to \(f(3)\).
\[ \begin{aligned} f(2) &= 4 & f(4) &= 16\\ f(2.5) &= 6.25 & f(3.5) &= 12.25\\ f(2.75) &= 7.5625 & f(3.25) &= 10.5625\\ f(2.9) &= 8.41 & f(3.1) &= 9.61 \\ f(2.99) &= 8.9401 & f(3.01) &= 9.0601\\ f(2.999) &= 8.994001 & f(3.001) &= 9.006001 \\ &\vdots & &\vdots \\ f(3) &= 9 & f(3) &= 9 \end{aligned} \]
Given a function \(f\), a fixed input \(x=a\), and a real number \(L\), we say that \(f\) has limit \(L\) as \(x\) approaches \(a\), and write
\[ \lim_{x \to a} f(x) = L, \]
provided that we can make \(f(x)\) as close to \(L\) as we like by taking \(x\) sufficiently close (but not equal) to \(a\). If we cannot make \(f(x)\) as close to a single value as we would like as \(x\) approaches \(a\), then we say that \(f\) does not have a limit \(L\) as \(x\) approaches \(a\).
Example: Find:
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We say that \(f\) has limit \(L_1\) as \(x\) approached \(a\) from the left and write \[ \lim_{x \to a^-} f(x) = L_1 \]
provided that we can make the value of \(f(x)\) as close to \(L_1\) as we like by taking \(x\) sufficiently close to \(a\), while always having \(x < a\). We call \(L_1\) the left-hand limit of \(f\) as \(x\) approaches \(a\).
We say that \(f\) has limit \(L_2\) as \(x\) approached \(a\) from the right and write
\[ \lim_{x \to a^+} f(x) = L_2 \]
provided that we can make the value of \(f(x)\) as close to \(L_2\) as we like by taking \(x\) sufficiently close to \(a\), while always having \(x > a\). We call \(L_1\) the right-hand limit of \(f\) as \(x\) approaches \(a\).
A function \(f\) has limit \(L\) as \(x \to a\) if and only if
\[ \lim_{x \to a^-} f(x) = L = \lim_{x \to a^+} f(x) \]
Example: Find:
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What does it mean for a function to be continuous? A function \(f\) is continuous at \(x=a\) provided that:
Example: Is \(f\) continuous at:
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There are some situations where a limit simply does not exist.
Example: Try to find the following limits:
\(\lim\limits_{x \to 1} x^2 + 2\).
\(\lim\limits_{t \to 0} \dfrac{\sin(5t)}{t}\).
\(\lim\limits_{y \to 1} \dfrac{x^2 - 1}{x - 1}\).
Recall that for a function \(f\) defined on an interval \([a, b]\), the average rate of change of \(f\) on \([a, b]\) is the quantity
\[ AV_{[a, b]} = \frac{f(b) - f(a)} {b - a}. \]
If we want to find the instantaneous rate of change at a point \(x = a\), imagine the average rate of change over an interval that is getting smaller and smaller and smaller.
For a function \(f\), the instantaneous rate of change of \(f\) at point \(x = a\) is the quantity \[ IV_{t=a} = \lim\limits_{h \to 0} AV_{[a,a+h]} = \lim\limits_{h \to 0} \frac{f(a + h) - f(a)} {h}. \]
Example: Consider \(S(x) = x^2 + x + 1\).