MATH 145 – Calculus I
November 6, 2025
Recall the Fundamental Theorem of Calculus from last lecture:
Suppose \(f(t)\) is a continuous function on the interval \([a, b]\) and that \(F(t)\) is an antiderivative of \(f(t)\). Then
\[ \int_a^b f(t) \, dt = F(b) - F(a) \]
The FTC says that you can evaluate \(\displaystyle\int_a^b f(x) \, dx\) if you can find the antiderivative of \(f(x)\). But how do we find \(\displaystyle\int f(x) \, dx\)?
There is no for integrals, so while it’s easy to find \(\dfrac{d}{dx} f(x) g(x)\), it may not be as easy to find \(\displaystyle\int f(x) g(x)\).
Remember that not all functions have clear antiderivatives, or antiderivatives which can be expressed in terms of elementary functions.
For example, the cumulative density function of the standard Normal distribution cannot be expressed easily and can generally only be found using numerical approximation methods.
\[ \Phi(z) = \mathbb{P}[Z \le z] = \frac{1}{\sqrt{2 \pi}} \int_{-\infty}^z e^{\frac{t^2}{2}} \, dt \]
We can, however, use the Chain Rule to give us a trick to help solve stubborn integrals.
Recall the Chain Rule:
\[ \frac{d}{dx} f(g(x)) = f'(g(x)) \, g'(x) \]
Then we can have:
\[ \int f'(g(x)) \, g'(x) \, dx = \int \frac{d}{dx} f(g(x)) \, dx = f(g(x)) \]
\[ \int f'(g(x)) \, g'(x) \, dx = \int f(u) \, du, \]
where \(u = g(x)\).
Examples:
Examples:
Examples:
\[ \int_a^b f'(g(x)) \, g'(x) \, dx = \int_{g(a)}^{g(b)} f(u) \, du, \]
Example: Find \(\displaystyle\int_0^1 e^{-x}(2e^{-x} + 3)^9 \, dx\).