MATH 145 – Calculus I
October 7, 2025
Recall that: If \(f(x)\) is differentiable at \(x = a\), the local linearization (or tangent line approximation) to \(f(x)\) near \(x = a\) is the function \[ y = L(x) \approx f(a) + f'(a)(x - a) \]
If \(f(x)\) is differentiable at \(x = a\), you can approximate it by its tangent line.
Example: Estimate \(\sqrt{36.1}\) using linear approximation.
Example: Estimate \(f(2.3)\) using \(x=2\) for \(f(x) = x^3 e^{-x^2}\), if we know that \(f'(x) = e^{-x^2} (3x^2 - 2x^4)\).
Example: Suppose that \(g(x)\) is a function with \(g(130) = 46\) and \(f'(130) = 2\). Estimate \(g(125.5)\).
Question: Where does the linear approximation \(l(x) = f(a) + f'(a) (x - a)\) intersect the \(x\)-axis?
Can we make this approximation better by moving the line? Can we iterate this?
This iterative algorithm is known as Newton’s Method:
Newton’s Method for approximating solutions to \(f(x) = 0\):
Example: Estimate the roots of \(f(x) = x^2 - 2\) using Newton’s method.
Example: Estimate the roots of \(f(x) = -x^2 + 2x + 2\) using Newton’s method.
Example: Estimate the roots of \(f(x) = x^3 - x^2 - 2x + 1\) using Newton’s method.